<\/p>\n
Multiple Choice Questions (Enter your answers on the enclosed answer sheet)<\/p>\n
\nChoose the one alternative that best completes the statement or answers the question.\n<\/p>\n
Write the word name for the given number.
\n1. 22,000,674\n<\/p>\n
a. Twenty-two million, six thousand seventy-four
\nb. Two million, two thousand, six hundred seventy-four <\/p>\n
c. Twenty-two hundred million, six hundred seventy-four <\/p>\n
d. Twenty-two million, six hundred seventy-four\n<\/p>\n
<\/p>\n
2. 2,601,400,070\n<\/p>\n
a. Two hundred sixty million, one hundred forty thousand, seventy
\nb. Two hundred sixty-one million, four hundred thousand, seven hundred
\nc. Two billion, six hundred one million, four hundred thousand, seventy
\nd. Two billion, six hundred one million, forty thousand, seventy\n<\/p>\n
Write each whole number in standard form.
\n3. Andy collected eighty-two thousand dollars for his campaign.\n<\/p>\n
a. 8200<\/p>\n
b. 82,000<\/p>\n
\nc. 80,002<\/p>\n
\nd. 802,000\n<\/p>\n
Add.
\n4. 7,651 + 3,874 =\n<\/p>\n
a. 11,525<\/p>\n
\nb. 34,636<\/p>\n
\nc. 31,487<\/p>\n
\nd. 12,678\n<\/p>\n
<\/p>\n
<\/p>\n
5. 148 + 55 =\n<\/p>\n
a. 226 <\/p>\n
b. 212 <\/p>\n
c. 203<\/p>\n
\nd. 213 <\/p>\n
<\/p>\n
Solve.\n<\/p>\n
6. A town\u2019s population in 1976 was 111,835. By the year 2000 it had increased by 25,952.
\nHow many people lived there in 2000?\n<\/p>\n
a. 137,787 people <\/p>\n
b. 138,787 people<\/p>\n
\nc. 136,787 people <\/p>\n
d. 137,887 people\n<\/p>\n
<\/p>\n
Subtract.
\n7. 9699 – 5554 =\n<\/p>\n
a. 9145<\/p>\n
\nb. 4145 <\/p>\n
c. 4037<\/p>\n
\nd. 4137\n<\/p>\n
Subtract. Use borrowing, if necessary.
\n8. 83,128 – 58,955 =\n<\/p>\n
a. 24,163 <\/p>\n
b. 24,123 <\/p>\n
c. 32,173 <\/p>\n
d. 24,173\n<\/p>\n
Multiply.
\n9. 62 \u00d7 9 =\n<\/p>\n
a. 551<\/p>\n
\nb. 658 <\/p>\n
c. 548<\/p>\n
\nd. 558\n<\/p>\n
Provide an appropriate response. <\/p>\n
10. What is x if x = 7 \u2219 1 \u2219 5 \u2219 0?\n<\/p>\n
a. x = 35<\/p>\n
\nb. x = 13<\/p>\n
\nc. x = 1<\/p>\n
\nd. x = 0 <\/p>\n
<\/p>\n
Simplify.
\n11. 63 \u00d7 83 – (6 – 4) =\n<\/p>\n
a. 286<\/p>\n
\nb. 300<\/p>\n
\nc. 2549 <\/p>\n
d. 5227\n<\/p>\n
<\/p>\n
Write using exponential notation.
\n12. 9 \u00d7 9 \u00d7 9 \u00d7 9\n<\/p>\n
a. 94 <\/p>\n
b. 94 <\/p>\n
c. 36 <\/p>\n
d. 92\n<\/p>\n
<\/p>\n
Round as indicated.
\n13. 7101 to the nearest hundred\n<\/p>\n
a. 7100<\/p>\n
\nb. 7110<\/p>\n
\nc. 7000 <\/p>\n
d. 7200\n<\/p>\n
<\/p>\n
Solve.\n<\/p>\n
14. A store has gross revenues of $6122, $6695, $4363, and $4601 in its first four weeks of
\nbusiness. What was the gross revenue for those four weeks?\n<\/p>\n
a. $21,881<\/p>\n
\nb. $21,781<\/p>\n
\nc. $20,781<\/p>\n
\nd. $22,331\n<\/p>\n
<\/p>\n
15. Leslie enjoys skiing in the winter. Last year she skied 21 times and spent a total of $693.
\nHow much did it cost her each time?\n<\/p>\n
a. $14,553 <\/p>\n
b. $672<\/p>\n
\nc. $34
\nd. $33 <\/p>\n
<\/p>\n
Write the fraction.\n<\/p>\n
16. Of the 157 students at a high school, 35 are sophomores. What fraction of the students are
\nsophomores?\n<\/p>\n
a. 157\/35 <\/p>\n
b. 35\/157 <\/p>\n
c. 35\/122 <\/p>\n
d. 122\/35\n<\/p>\n
<\/p>\n
Reduce the fraction by finding a common factor in the numerator and in the denominator and
\ndividing by the common factor.\n<\/p>\n
17. (55\/65)\n<\/p>\n
a. (55\/65) <\/p>\n
b. (5\/13) <\/p>\n
c. (11\/13) <\/p>\n
d. (11\/5)\n<\/p>\n
<\/p>\n
Identify if the whole number is prime or composite. <\/p>\n
18. 30\n<\/p>\n
a. Prime
\nb. Composite\n<\/p>\n
<\/p>\n
Write the improper fraction as a mixed or whole number. <\/p>\n
19. (252\/11)\n<\/p>\n
a. (11\/252)<\/p>\n
\nb. 252252\/11 <\/p>\n
c. 2521 52 <\/p>\n
d. 2210\/11\n<\/p>\n
<\/p>\n
Reduce the improper fraction.<\/p>\n
\n20. 99\/44\n<\/p>\n
<\/p>\n
Change to a mixed number and reduce. <\/p>\n
21. (344\/20)\n<\/p>\n
a. 17<\/p>\n
b.174\/5<\/p>\n
\nc. 171\/5<\/p>\n
\nd. 175\/4<\/p>\n
<\/p>\n
Multiply. Write the answer in simplest form. <\/p>\n
22. (3\/7) \u00d7 (1\/9) =\n<\/p>\n
a. (1\/21) <\/p>\n
b. (1\/4)<\/p>\n
\nc. (7\/27) <\/p>\n
d. (4\/63)\n<\/p>\n
<\/p>\n
Solve. Write the answer in simplest form.\n<\/p>\n
23. Julie\u2019s Cinema received $5460 in movie admission tickets for one day. About (3\/13) of this
\namount was for G-rated movies. Find the amount of money received from G-rated movies.\n<\/p>\n
a. $1260<\/p>\n
\nb. $140
\nc. $23,660<\/p>\n
\nd. $420\n<\/p>\n
<\/p>\n
Divide, if possible. Write the answer in simplest form. <\/p>\n
24. 55\/9 \u00f7 10 =\n<\/p>\n
a. (6\/9) <\/p>\n
b. (4\/9) <\/p>\n
c. (5\/8) <\/p>\n
d. (5\/9)\n<\/p>\n
<\/p>\n
25. 5\u00f7 45\/6 =\n<\/p>\n
a. 13\/29<\/p>\n
\nb. 13\/28 <\/p>\n
c. 14\/29 <\/p>\n
d. 23\/29 <\/p>\n
<\/p>\n
Add or subtract. Simplify the answer. <\/p>\n
26. (52\/75) – (29\/75) =\n<\/p>\n
a. (23\/150)<\/p>\n
\nb. 12\/25
\nc. (23\/75)<\/p>\n
\nd. 208\/75\n<\/p>\n
<\/p>\n
Add or subtract. Express the answer as a mixed number. <\/p>\n
27. 191\/7 + 135\/7 + 75\/7 =\n<\/p>\n
a. 404\/7<\/p>\n
\nb. 394\/7 <\/p>\n
c. 40
\nd. 414\/7\n<\/p>\n
<\/p>\n
28. 14 – (2\/9) =\n<\/p>\n
a. 137\/9 <\/p>\n
b. 117\/9 <\/p>\n
c. 147\/9 <\/p>\n
d. 13\n<\/p>\n
<\/p>\n
Add or subtract.
\n29. 194\/9 + 194\/9 =\n<\/p>\n
a. 378\/9<\/p>\n
\nb. 398\/9<\/p>\n
\nc. 388\/9 <\/p>\n
d. 198\/9\n<\/p>\n
<\/p>\n
Write the words for the dollar amount as you would on a check.<\/p>\n
\n30. $200.58\n<\/p>\n
a. Two hundred dollars and 58 cents<\/p>\n
\nb. Two hundred and (58\/100) dollars <\/p>\n
c. Two hundred (58\/100) dollars
\nd. Two hundred dollars and 58 <\/p>\n
<\/p>\n
Insert <, >, or = between each pair of numbers to form a true statement. <\/p>\n
31. 0.463 _____ 0.46300<\/p>\n
a. ><\/p>\n
\nb.< <\/p>\n
c. =<\/p>\n
<\/p>\n
Arrange in order from smallest to largest.
\n32. 6.09, 6.9, 6.099, 6.999\n<\/p>\n
a. 6.999, 6.9, 6.099, 6.09<\/p>\n
\nb. 6.09, 6.9, 6.099, 6.999<\/p>\n
\nc. 6.099, 6.09, 6.999, 6.9<\/p>\n
\nd. 6.09, 6.099, 6.9, 6.999\n<\/p>\n
<\/p>\n
Solve.\n<\/p>\n
33. According to his ultra-precise scale, Jeremy gained 3.249 pounds in a three-month period.
\nRound this amount off to the nearest hundredth.\n<\/p>\n
a. 3.2 pounds<\/p>\n
\nb. 3.25 pounds<\/p>\n
\nc. 0.25 pounds <\/p>\n
d. 3.26 pounds\n<\/p>\n
<\/p>\n
Divide.
\n34. (2.24) divided by 7\n<\/p>\n
a. 1.32<\/p>\n
\nb. 13.2<\/p>\n
\nc. 3.2 <\/p>\n
d. 0.32\n<\/p>\n
35. (3.9732) divided by 516\n<\/p>\n
a. 0.0077<\/p>\n
\nb. 0.0087 <\/p>\n
c. 0.78
\nd. 0.77 <\/p>\n
<\/p>\n
36. (163.2186) divided by 2.8 Round to the nearest hundredth.<\/p>\n
a. 58.33 <\/p>\n
b. 58.332<\/p>\n
\nc. 58.29 <\/p>\n
d. 5.83\n<\/p>\n
<\/p>\n
Solve.
\n37. 0.028 \u00d7 n = 0.7\n<\/p>\n
a. 24.8
\nb. 26
\nc. 25
\nd. 0.0196<\/p>\n
Write as an equivalent decimal. If a repeating decimal is obtained, use notation such as 0.4,
\n0.23, or 0.567\n<\/p>\n
38. 317\/20\n<\/p>\n
a. 3.85 <\/p>\n
b. 3.855 <\/p>\n
c. 3.85 <\/p>\n
d. 3.85\n<\/p>\n
Simplify by using the order of operations. Round your answer to the nearest hundredth.
\n39. 2.9 + (13.9 – 3.8) \u2219 7.2\n<\/p>\n
a. -38.36<\/p>\n
\nb. 99.18<\/p>\n
\nc. 75.62<\/p>\n
\nd. 93.60\n<\/p>\n
<\/p>\n
First round each number to one non-zero digit. Then perform the calculation using the rounded
\nnumbers to obtain an estimate.\n<\/p>\n
40. 51.7 – 5.17\n<\/p>\n
a. estimate: 45 <\/p>\n
b. estimate: 55 <\/p>\n
c. estimate: 54<\/p>\n
\nd. estimate: 46 <\/p>\n
<\/p>\n
Round as indicated.<\/p>\n
\n41. Round 25.4564 to the nearest hundredth.\n<\/p>\n
a. 25.56<\/p>\n
\nb. 25.36<\/p>\n
\nc. 25.46 <\/p>\n
d. 25.44\n<\/p>\n
<\/p>\n
Divide.
\n42. (0.00786) divided by 0.04\n<\/p>\n
a. 0.201<\/p>\n
\nb. 0.1965<\/p>\n
\nc. 0.1977<\/p>\n
\nd. 0.1974\n<\/p>\n
<\/p>\n
Write the ratio in lowest terms.
\n43. 20:14\n<\/p>\n
a. (7\/10)<\/p>\n
\nb. (20\/14) <\/p>\n
c. (14\/20)<\/p>\n
\nd. (10\/7)\n<\/p>\n
<\/p>\n
Write the following as a rate in lowest terms.
\n44. $685 for 20 rolls of film\n<\/p>\n
a. ($137\/20 rolls of film)<\/p>\n
\nb. ($685\/4 rolls of film)<\/p>\n
\nc. ($5\/20 rolls of film)
\nd. ($137\/4 rolls of film)\n<\/p>\n
<\/p>\n
Write the rate as a unit rate.
\n45. 8 cents for 4 marbles
\na. 2 cents\/marble\n<\/p>\n
b. 0.5 cents\/marble<\/p>\n
\nc. 12 cents\/marbles <\/p>\n
d. 32 cents\/marble <\/p>\n
<\/p>\n
46. 420 people in 20 buses\n<\/p>\n
a. 210 people\/bus<\/p>\n
\nb. 400 people\/bus<\/p>\n
\nc. 21 people\/bus
\nd. 0.048 person\/bus\n<\/p>\n
<\/p>\n
Solve using a proportion. Round your answer to the nearest hundredth when necessary.\n<\/p>\n
47. Find which is the better buy (lower cost per ounce) by finding each unit price rounded to
\nthree decimal places if necessary.\n<\/p>\n
Jelly:
\n$1.41 for 6 ounces. $2.35 for 10 ounces<\/p>\n
a. $2.35 for 10 ounces
\nb. $1.41 for 6 ounces
\nc. Both cost the same per ounce. <\/p>\n
d. None of the above.\n<\/p>\n
<\/p>\n
Write as a proportion.\n<\/p>\n
48. If 60 pounds of potatoes is enough to feed 150 children, then 68 pounds should be the right
\namount for 170 children.\n<\/p>\n
a. (60 pounds\/150 children) = (170 children\/68 pounds)<\/p>\n
\nb. (150 children\/60 pounds) = (68 pounds\/170 children)<\/p>\n
\nc. (60 pounds\/150 children) = (68 pounds\/170 children) <\/p>\n
d. (60 pounds\/170 children) = (68 pounds\/150 children)\n<\/p>\n
<\/p>\n
Solve each proportion for the given variable.<\/p>\n
\n49. (n\/22) = (6\/11)\n<\/p>\n
a. 12
\nb. 40c. 3
\nd. 24\n<\/p>\n
<\/p>\n
50. (x\/3.9) = (0.08\/9) Round to the nearest hundredth.\n<\/p>\n
a. 0.03
\nb. 438.75
\nc. 2.81
\nd. 28.85 <\/p>\n
<\/p>\n
Find the value of n. Round to the nearest hundredth if necessary. <\/p>\n
51. (1200 revolutions\/20 minutes) = (n revolutions\/21 minutes)\n<\/p>\n
a. 1134<\/p>\n
\nb. 1260<\/p>\n
c. 2.86<\/p>\n
\nd. 25,200\n<\/p>\n
<\/p>\n
52. (n pounds\/4 kilograms) = (11.35 pounds\/5 kilograms)\n<\/p>\n
a. 8.63 <\/p>\n
b. 9.08<\/p>\n
\nc. 2.84<\/p>\n
\nd. 9.53\n<\/p>\n
<\/p>\n
Solve using a proportion. Round your answer to the nearest hundredth when necessary.\n<\/p>\n
53. On an architect\u2019s blueprint, 1 inch corresponds to 12 feet. If an exterior wall is 68 feet long,
\nfind how long the blueprint measurement should be. Write answer as a mixed number if
\nnecessary.\n<\/p>\n
a. 113\/17 inches<\/p>\n
\nb. 51 inches
\nc. 5inches <\/p>\n
d. 68 inches\n<\/p>\n
<\/p>\n
Solve.\n<\/p>\n
54. In a survey of 100 people, 8 preferred relish on their hot dogs. What percent preferred
\nrelish?\n<\/p>\n
a. 0.8% <\/p>\n
b. 0.08%<\/p>\n
\nc. 2\/25% <\/p>\n
d. 8%\n<\/p>\n
<\/p>\n
Write as a decimal.
\n55. 0.079%\n<\/p>\n
a. 0.00079 <\/p>\n
b. 7.9
\nc. 0.0079
\nd. 0.000079 <\/p>\n
<\/p>\n
Write the percent as a decimal.<\/p>\n
\n56. In the last election Mr. Thomas received 0.2% of the vote.\n<\/p>\n
a. 0.02<\/p>\n
\nb. 2
\nc. 0.2
\nd. 0.002\n<\/p>\n
<\/p>\n
Write as a fraction or as a mixed number <\/p>\n
57. 50%<\/p>\n
a. 5<\/p>\n
b. 1\/4<\/p>\n
c. 1\/2<\/p>\n
d. 1<\/p>\n
<\/p>\n
58. 171 3\/7%\n<\/p>\n
a. 171\/7 <\/p>\n
b. 33\/7 <\/p>\n
c. 6\/7
\nd. 15\/7\n<\/p>\n
<\/p>\n
Solve. Round decimals to the nearest thousandth and percents to the nearest tenth of a percent.
\n59. Write the equivalent decimal and percent for (7\/12).\n<\/p>\n
a. 0.703;70.3%<\/p>\n
\nb. 0.583;58.3% <\/p>\n
c. 0.703;703% <\/p>\n
d. 0.583;5.83%\n<\/p>\n
<\/p>\n
Solve.
\n60. 37% of what is 74?\n<\/p>\n
a. 0.5<\/p>\n
\nb. 50
\nc. 2000<\/p>\n
\nd. 200 <\/p>\n
<\/p>\n
61. A $210 camera is on sale at 5% off. How much will the camera cost?\n<\/p>\n
a. $2089.50<\/p>\n
\nb. $1.05
\nc. $199.50 <\/p>\n
d. $10.50\n<\/p>\n
<\/p>\n
62. A stock broker is paid $600 per month plus 2% of the total sales of stocks that she sells.
\nLast month Cora sold $68,000 worth of stock. What was her total income for the month?\n<\/p>\n
a. $13,600<\/p>\n
\nb. $1360<\/p>\n
\nc. $14,200 <\/p>\n
d. $1960\n<\/p>\n
<\/p>\n
63. Raya borrowed $10,000 to finish college at an interest rate of 6.5% per year. How much
\ninterest will Raya need to pay next year?\n<\/p>\n
a. $10,650 <\/p>\n
b. $6500 <\/p>\n
c. $16,500<\/p>\n
\nd. $650\n<\/p>\n
<\/p>\n
Convert. When necessary, round the answer to two decimal places.
\n64. 2pounds = ____ ounces\n<\/p>\n
a. 52 <\/p>\n
b. 44<\/p>\n
\nc. 32 <\/p>\n
d. 45\n<\/p>\n
<\/p>\n
Solve the problem.\n<\/p>\n
65. Dennis is hosting a dinner party. His recipe calls for 4 ounces of chicken per person. If he
\nis expecting 24 guests, how many pounds of chicken should he buy? Round your answer to
\ntwo decimal places if necessary.\n<\/p>\n
a. 1536 pounds <\/p>\n
b. 96 pounds
\nc. 6 pounds
\nd. 12 pounds <\/p>\n
<\/p>\n
66. A rectangular window is 3 feet 10 inches wide and 6 feet 9 inches tall. If the window needs
\nto be sealed with insulation that costs $1.22 per inch, how much will it cost to insulate the
\nperimeter?\n<\/p>\n
a. $265.96<\/p>\n
\nb. $309.88<\/p>\n
\nc. $26.60<\/p>\n
\nd. $319.15\n<\/p>\n
<\/p>\n
Change to a convenient unit of measure and add.
\n67. 53 cm + 9 dm + 19 mm\n<\/p>\n
a. 1449 cm <\/p>\n
b. 144.9 cm<\/p>\n
\nc. 243.9 cm<\/p>\n
\nd. 81 cm\n<\/p>\n
<\/p>\n
Write true or false for the statement.
\n68. A grown man might weigh 101 kilograms.\n<\/p>\n
a. True <\/p>\n
b. False<\/p>\n
<\/p>\n
Perform the conversion. Round to the nearest hundredth when necessary.
\n69. 33 L to qt\n<\/p>\n
a. 14.98 qt <\/p>\n
b. 39.60 qt <\/p>\n
c. 31.22 qt <\/p>\n
d. 34.88qt\n<\/p>\n
<\/p>\n
Convert as indicated. When necessary, round to the nearest tenth of a degree.
\n70. 230\u00b0 F to degrees Celsius\n<\/p>\n
a. 446\u00b0 C<\/p>\n
\nb. 145.6\u00b0 C<\/p>\n
\nc. 110\u00b0 C <\/p>\n
d. 95.8\u00b0 C <\/p>\n
<\/p>\n
Solve.\n<\/p>\n
71. The flow rate of a safety discharge pipe at a dam is rated for a maximum of 204,000 gallons
\nper hour. Convert this rate to pints per second. Round your answer to the nearest tenth.
\nDuring a flood, the flow rate at the dam is measured as 428 pints per second. Could the
\nsafety discharge pipe safely handle this flow rate?\n<\/p>\n
a. 226.7 pints per second; no <\/p>\n
b. 214.8 pints per second; no <\/p>\n
c. 566.7 pints per second; yes <\/p>\n
d. 453.3 pints per second; yes\n<\/p>\n
<\/p>\n
72. Brian and Heather drove 426 miles in 6 hours. What was their average speed in kilometers
\nper hour? (Round your answer to the nearest whole number, if necessary.)\n<\/p>\n
a. 686 km\/hr <\/p>\n
b. 44 km\/hr <\/p>\n
c. 114 km\/hr <\/p>\n
d. 71 km\/hr\n<\/p>\n
<\/p>\n
Perform the conversion. Round to the nearest hundredth when necessary.
\n73. 898 yd = ____ m\n<\/p>\n
a. 821.13 <\/p>\n
b. 2945.44 <\/p>\n
c. 978.82 <\/p>\n
d. 273.89 <\/p>\n
<\/p>\n
Find the area of the rectangle or square.
\n75. Length = 0.53 m, width = 0.24 m\n<\/p>\n
a. 0.2544 m to power of ((2))<\/p>\n
\nb. 0.77 m to power of ((2))
\nc. 1.54 m to power of ((2))
\nd. 0.1272 m to power of ((2))\n<\/p>\n
<\/p>\n
Find the perimeter and area of the rhombus.
\n76. The height is 8 m and the base is 17 m\n<\/p>\n
a. P = 34 m, A = 68 m to power of ((2)) <\/p>\n
b. P = 17 m, A = 25 m to power of ((2)) <\/p>\n
c. P = 68 m, A = 136 m to power of ((2)) <\/p>\n
d. P = 136 m, A = 68 m to power of ((2))\n<\/p>\n
<\/p>\n
Find the area of the trapezoid.
The height is 5 m and the bases are 7 m and 8 m.\n<\/p>\n
a. 140 m to power of ((2)) <\/p>\n
b. 75 m to power of ((2)) <\/p>\n
c. 10 m to power of ((2)) <\/p>\n
d. 37.5 m to power of ((2))\n<\/p>\n
<\/p>\n
Find the perimeter of the triangle.
An equilateral triangle whose side measures 8 mi\n<\/p>\n
a. 23 mi <\/p>\n
b. 32 mi<\/p>\n
\nc. 24 mi<\/p>\n
\nd. 16 mi\n<\/p>\n
<\/p>\n
Find the diameter of a circle if the radius has the value given. <\/p>\n
r = 22 ft\n<\/p>\n
a. 44 ft
\nb. 1519.76 ft<\/p>\n
\nc. 69.08 ft
\nd. 11 ft <\/p>\n
<\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"
Multiple Choice Questions (Enter your answers on the enclosed answer sheet) Choose the one alternative that best completes the statement or answers the question. Write the word name for the given number. 1. 22,000,674 a. Twenty-two million, six thousand seventy-four b. Two million, two thousand, six hundred seventy-four c. Twenty-two hundred million, six hundred seventy-four […]<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":"","_joinchat":[]},"categories":[1],"tags":[],"_links":{"self":[{"href":"https:\/\/qualityassignments.net\/wp-json\/wp\/v2\/posts\/165842"}],"collection":[{"href":"https:\/\/qualityassignments.net\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/qualityassignments.net\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/qualityassignments.net\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/qualityassignments.net\/wp-json\/wp\/v2\/comments?post=165842"}],"version-history":[{"count":0,"href":"https:\/\/qualityassignments.net\/wp-json\/wp\/v2\/posts\/165842\/revisions"}],"wp:attachment":[{"href":"https:\/\/qualityassignments.net\/wp-json\/wp\/v2\/media?parent=165842"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/qualityassignments.net\/wp-json\/wp\/v2\/categories?post=165842"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/qualityassignments.net\/wp-json\/wp\/v2\/tags?post=165842"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}