<\/p>\n
Week 2 Assignment<\/h1>\n
Question 1<\/p>\n
- \n
- Compute the weighted mean for the following data.<\/li>\n<\/ol>\n
![](\"https:\/\/content.grantham.edu\/at\/BA215\/2015\/wk-2-assignment-image-1.png\")
<\/p>\nQuestion 2<\/p>\n
- \n
- If P(A) = 0.50, P(B) = 0.40, and P(A \u222a B) = 0.88, then P(B | A) =<\/li>\n<\/ol>\n
Question 3<\/p>\n
Six vitamin and three sugar tablets identical in appearance are in a box. One tablet is taken at random and given to Person A. A tablet is then selected and given to Person B. What is the probability that<\/p>\n
- \n
- Person A was given a vitamin tablet?<\/li>\n
- Person B was given a sugar tablet given that Person A was given a vitamin tablet?<\/li>\n
- neither was given vitamin tablets?<\/li>\n
- both were given vitamin tablets?<\/li>\n
- exactly one person was given a vitamin tablet?<\/li>\n
- Person A was given a sugar tablet and Person B was given a vitamin tablet?<\/li>\n
- Person A was given a vitamin tablet and Person B was given a sugar tablet?<\/li>\n<\/ol>\n<\/div>\n","protected":false},"excerpt":{"rendered":"
Week 2 Assignment Question 1 Compute the weighted mean for the following data. Question 2 If P(A) = 0.50, P(B) = 0.40, and P(A \u222a B) = 0.88, then P(B | A) = Question 3 Six vitamin and three sugar tablets identical in appearance are in a box. One tablet is taken at random and […]<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":"","_joinchat":[]},"categories":[1],"tags":[],"_links":{"self":[{"href":"https:\/\/qualityassignments.net\/wp-json\/wp\/v2\/posts\/171038"}],"collection":[{"href":"https:\/\/qualityassignments.net\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/qualityassignments.net\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/qualityassignments.net\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/qualityassignments.net\/wp-json\/wp\/v2\/comments?post=171038"}],"version-history":[{"count":0,"href":"https:\/\/qualityassignments.net\/wp-json\/wp\/v2\/posts\/171038\/revisions"}],"wp:attachment":[{"href":"https:\/\/qualityassignments.net\/wp-json\/wp\/v2\/media?parent=171038"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/qualityassignments.net\/wp-json\/wp\/v2\/categories?post=171038"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/qualityassignments.net\/wp-json\/wp\/v2\/tags?post=171038"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
- If P(A) = 0.50, P(B) = 0.40, and P(A \u222a B) = 0.88, then P(B | A) =<\/li>\n<\/ol>\n